An elastic cord can be stretched to it's elastic limit by a load of 2newton.if a 35cm length when the cord is extended 0.6m by a force of 0.5newton,what will be the length of the cord when the stretched force is 2.5newton?

Answer 1

To find the length of the cord when the stretched force is 2.5 newtons, we can use the concept of Hooke's law, which states that the extension of an elastic material is directly proportional to the applied force.

Let L1 be the original length of the cord when the load of 2 newtons stretches it to its elastic limit, and L2 be the length of the cord when it is extended by a force of 0.5 newtons.

Applying Hooke's law, we can write:

L2 = L1 + x

where x is the extension of the cord due to the 0.5 newton force.

Given that L1 = 35 cm and x = 0.6 m (since the cord is extended by 0.6 m), we can convert the length and extension to meters:

L1 = 35 cm = 0.35 m
x = 0.6 m

Now we can solve for L2:

L2 = 0.35 m + 0.6 m = 0.95 m

So, the length of the cord when the stretched force is 2.5 newtons would be 0.95 meters.