an eiastic cord can be stretched to its elastic limit by a load of 2N.if a 35cm length of the cord is extended 0.6cm by a force of 0.5N,what will be the length of the cord when the stretching force is 2.5cm.

Answer 1

force is direcdtly proportional to lenght

f2/f1=x2/x1 where x is stretch

F2=.5*2.5/.6

F2=about 2 N