First, note that you can't throw all of those numbers after 0.0049 away. You have 4 places in 0.4835 and you should have AT LEAST 4 in the answer. I usually carry one more place and round at the end.
Ca^2+ + EDTA ==> Complex
mols EDTA = mols CaCO3
Then M EDTA = mols/L solution = 0.004830/0.03518 = ? M EDTA
An EDTA solution is standardised against high-purity CaCO3 by dissolving 0.4835 g CaCO3 in HCl, adjusting the pH to 10 with ammoniacal buffer and titrated with an EDTA solution. If 35.18ml were required for the titration, what was the molarity of the EDTA solution?
Step 1.
Moles CaCO3 = 0.4835/100.0869 g/mol
= 0.0049 mol.
Step 2. ??
If anyone could help that would be great, Thank you.
1 answer
3 answers