An early major objection to the idea that

Question

Earth is spinning on its axis was that Earth
would turn so fast at the equator that people
would be thrown into space.
Given : radius earth = 6.37 × 10^6 m ,
mass earth = 5.98 × 10^24 kg ,
radius moon = 1.74 × 10^6 m , and
g = 9.8 m/s^2.
Show the error in this logic by calculating
the speed of a 90.6 kg person at the equator

Answer 1

.

Answer: The speed of a 90.6 kg person at the equator can be calculated using the equation for centripetal acceleration:
a = (v^2)/r
where a is the centripetal acceleration, v is the velocity, and r is the radius of the Earth.

Substituting the given values, we get:
a = (v^2)/(6.37 × 10^6 m)

Solving for v, we get:
v = sqrt(a*r)

Substituting the given values, we get:
v = sqrt((9.8 m/s^2)*(6.37 × 10^6 m))

Therefore, the speed of a 90.6 kg person at the equator is 463.7 m/s, which is much lower than the escape velocity of the Earth (11.2 km/s). This shows that the objection is incorrect, as people would not be thrown into space due to the Earth's rotation.