An e−1 is released by an electron microscope at 3.00 × 106 m/s.

Question

Determine  in meters using the de Broglie relation
Substitute kgˑm2/s2 for J and show all units.
Then, convert  to pm and show the conversion factor.
Determine the kinetic energy using EK = (1/2)mv2, where v is velocity.
Show all units.

So would it be 9.10938 x10^-31 j Gould would you convert that?

Answer 1

I'm a little unsure of what you want. I assume that "box" I see and can't read is lamda. lambda = h/mv
So you plug in h, you have m right for the electron, and you have v listed, solve for wavelength.
If you want KE use KE = 1/2 mv^2 and units will be in J.
If you want to convert lambda in meters to pm, that is ?m x (10^12 pm/m) = ?