An award is being plated with pure gold before it its presented to a recipient. If the area of the award is 55.0 cm^3 and will be plated with 3.00 micrometers of Au, what mass of Au will be plated on the award? The density of Au is 19.3 g/cm^3.

Answer 1

AREA is NOT in cm^3 but in cm^2

Should I trust the rest of what you tyoed?
Oh well

3 * 10^-6 meters(10^2 cm/m) = 3*10^-4 cm

3*10^-4 * .55*10^2 = 1.65*10^-2 cm^3

19.3 g/cm^3 * 1.65*10^-2 cm^3 = .318 g

Answer 2

So the volume will be area x thickness = 55 cm x 3E-4 cm = ?
mass = volume x density = ?

Answer 3

this is what was on my worksheet