An average American household uses about 1.04×10^5 kilowatt hours of electricity, a year. If a Power Station generates 2.496×10^10 Sheila hours per year how many households can it serve? Write your answer in scientific notation expressed to the exact decimal place.

1 answer

To find out how many households can be served by the Power Station, we need to divide the total generated Sheila hours by the amount of electricity an average household uses in a year.

Total Sheila hours generated by the Power Station = 2.496×10^10
Electricity used by an average household in a year = 1.04×10^5

So, the number of households served = (2.496×10^10) / (1.04×10^5)

To divide these numbers, we subtract the exponents: 10^10 / 10^5 = 10^(10-5) = 10^5

Therefore, the number of households served = 2.496×10^10 / 1.04×10^5 = 2.4×10^5.

The answer, expressed in scientific notation to the exact decimal place, is 2.4×10^5.