An average American household uses about 1.04×10^4

kWh (kilowatt hours) of electricity a year. If a power station generates 2.496×10^10
kWh per year, how many households can it serve? Write your answ

1 answer

To determine how many households can be served by the power station, we can divide the total electricity generated by the power station by the average electricity consumption of a household.

Given:

  • Average electricity consumption per household: \( 1.04 \times 10^4 \) kWh
  • Total electricity generated by the power station: \( 2.496 \times 10^{10} \) kWh

Now we can calculate the number of households served:

\[ \text{Number of households} = \frac{\text{Total electricity generated}}{\text{Average electricity consumption per household}} \]

Substituting in the values:

\[ \text{Number of households} = \frac{2.496 \times 10^{10} \text{ kWh}}{1.04 \times 10^{4} \text{ kWh}} \]

Calculating this:

\[ \text{Number of households} = \frac{2.496 \times 10^{10}}{1.04 \times 10^{4}} = \frac{2.496}{1.04} \times 10^{10 - 4} \]

\[ \frac{2.496}{1.04} \approx 2.4 \quad \text{and} \quad 10^{10 - 4} = 10^{6} \]

So,

\[ \text{Number of households} \approx 2.4 \times 10^{6} \]

Therefore, the power station can serve approximately 2.4 million households.