Write the equation and balance it.
H2SO4 + 2NaHCO3 ==> Na2SO4 + 2CO2 + 2H2O
(I think that's balanced but check it out.)
Convert 85 mL of 2.4 M H2SO4 to mols remembering that M x L = mols.
Convert mols H2SO4 to mols NaHCO3 using the coefficients in the balanced equation.
Then use M NaHCO3 = # mols/L. You know M of NaHCO3 and # mols, the only unknown is L.
an auto mechanic spills 85 mL of 2.4 M H2SO4 solution from a rebuilt auto battery. how many mL of 1.2 M NaHCO3 must be poured on the spill to react completely with the sulfuric acid?
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