An Australian emu is running due north in a straight line at a speed of 13.0 m/s and slows down to a speed of 10.6 m/s in 4.0 s. Assuming that the acceleration remains the same, what is the bird's velocity after an additional 2.0 s has elapsed?

Answer 1

v=u+ft or f=(v-u)/t=(10.6-13)/4=-2.4/4
=-0.6m/s^2.
Now the u is 10.6m/s and f=-0.6m/s^2
v=u+ft=10.6-0.6*2=10.6-1.2=9.4 m/s^2