An Australian emu is running due north in a straight line at a speed of 13.0 m/s and slows down to a speed of 11.0 m/s in 2.40 s. (a) What is the magnitude and direction of the bird’s acceleration? (b) Assuming that the acceleration remains the same, what is the bird’s velocity after an additional 1.50 s has elapsed?

asked by Anonymous

8 years ago

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(a) a = (11-13 m/s)/2.4s = -2/2.4 m/s^2
(b) v = 11 - at, so use t=1.5

answered by Steve

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Question

An Australian emu is running due north in a straight line at a speed of 13.0 m/s and slows down to a speed of 11.0 m/s in 2.40 s. (a) What is the magnitude and direction of the bird’s acceleration? (b) Assuming that the acceleration remains the same, what is the bird’s velocity after an additional 1.50 s has elapsed?

1 answer

(a) a = (11-13 m/s)/2.4s = -2/2.4 m/s^2
(b) v = 11 - at, so use t=1.5

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Steve · Answer

(a) a = (11-13 m/s)/2.4s = -2/2.4 m/s^2 (b) v = 11 - at, so use t=1.5