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An Atwood's machine is built from m1=1kg and m2=2kg. The massless string is passed over a frictionless massless pulley. When the system is released from rest, what is the tension in the string?
The answer is 68, this is for my finals review And my professor said the questions were going to be similar to the ones on the review, Anything helps. Thanks I'm advance.
2 answers
the masses are linked by the string and have the same acceleration ... one upward and the other downward
f = m a ... a = f / m
(t - m1 g) / m1 = (m2 g - t) / m2
2t - 2g = 2g - t ... 3t = 4g
... t = 4/3 g
the largest mass is 2 kg ... it gives
about 20 N of force with the system at rest
68 is not correct
f = m a ... a = f / m
(t - m1 g) / m1 = (m2 g - t) / m2
2t - 2g = 2g - t ... 3t = 4g
... t = 4/3 g
the largest mass is 2 kg ... it gives
about 20 N of force with the system at rest
68 is not correct
1 answer