An atom of helium has a mass of 6.8 x 10^-27 kg. If a room contains 9 x 10^22 atoms of helium, what is the mass of helium in the room?

Answer 1

To find the mass of helium in the room, we need to multiply the mass of one helium atom by the total number of helium atoms in the room.

The mass of one helium atom is given as 6.8 x 10^-27 kg.

The total number of helium atoms in the room is given as 9 x 10^22 atoms.

Multiplying these values together, we get:

(6.8 x 10^-27 kg/atom) * (9 x 10^22 atoms) = 6.12 x 10^-4 kg

Therefore, the mass of helium in the room is 6.12 x 10^-4 kg.