An athlete throws a javlin with velocity of 20m/s at angle of 15 degree with the horizontal . How far the javlin would hit the ground from the point of projection?

Answer 1

the time in air is due to the initial vertical velocity, and gravity.
hf=hi+V*sin15*t-4.9t^2, find time t in air.

t=sqrt(20sin15/4.9)
now how far?
howfar=horizVelocity*timeinair
=20cos15*t