Fixed Answer
Us= 1/2kx^2
=1/2(5286.0)(.40)^2=422.88 J
an athlete stretches a spring an extra 40.0 cm. how much energy has he transferred to the spring, if the spring constant is 5286.0 N/m?
Us= 1/2kx^2
=1/2(5286.0)(.40)=1057.2 J
Thanks!
1 answer
1 answer