he is halfway through his jump when he reaches the top. That is when the vertical speed has gone to zero. That will be when
9.14 sin35° - 9.81t = 0
t = 9.14 sin35°/9.81
So he will be in the air for 2t seconds by the time he is back on the ground.
An athlete competing in the long jump leaves the ground with a speed of 9.14 m/s at an angle of 35° above the horizontal. How long does the athlete stay in the air, assuming no significant air resistance?
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