An athlete at the gym holds a 5.29 kg steel ball in his hand. His arm is 67.0 cm long and has a mass of 4.57 kg. What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor?

Answer 1

You have to assume a cg for the arm. Assuming midway...

4.57*67/2+5.29*67 in N-cm of torque

Answer 2

What is the magnitude of the torque about his shoulder if he holds his arm straight, but 43.8° below horizontal?

I tried multiplying the torque force by sin43.8 but it was wrong :(