Asked by Vishnu
                An athlete at the gym holds a 4.33 kg steel ball in his hand. His arm is 68.7 cm long and has a mass of 4.69 kg. What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? 
            
            
        Answers
                    Answered by
            bobpursley
            
    Looking at the ball and his arm, and assuming the mass of the arm is at the center of the arm...
torque=massball*length + massarm*length/2
    
torque=massball*length + massarm*length/2
                    Answered by
            Vishnu
            
    Should the lenght be in centimetres or metres and the mass of the ball in kilograms?
    
                    Answered by
            bobpursley
            
    Normally, it does not matter if you place units on your answer.  Standard form is n-meters.
    
                    Answered by
            Vishnu
            
    What is the magnitude of the torque about his shoulder if he holds his arm straight, but 46.6° below horizontal? 
    
                    Answered by
            jACK
            
    gOOD QUESTION
i would think it would be,
torque=massball*length*sin46.6 + massarm*length/2cos*46.6
    
i would think it would be,
torque=massball*length*sin46.6 + massarm*length/2cos*46.6
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