Do you know 45 degrees gives max distance?
u = 4.9 cos 45 = .707 (4.9) = 3.46 m/s
12 = 3.46 t
t = 3.47 seconds in air
t going up = 3.47/2 = 1.73 s upward
v = Vi - g t
Vi = 4.9 sin 45 = 3.46
v = 0 at top
0 = 3.46 - g (1.73)
g = 2 m/s^2
max height is average speed up time time up
= (3.46/2) * 1.73 = 3 meters
An astronaut on the planet Vimrom IV finds that she can jump a maximum horizontal distance of 12.00 m if her initial speed is 4.90 m/s. What is the acceleration due to gravity on this planet?
In the previous problem, what is the maximum height about the ground reached by the astronaut?
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