An Astronaut on the Moon drops a rock straight downward from a height of 1.25 meters. If the acceleration of gravity on the Moon is 1.62 meters per second squared, what is the speed of the rock just before it lands?

Answer 1

V = sqrt(2 a X) when the initial velocity is zero.

a is the acceleration rate
X is the distance fallen
Solve for V

Answer 2

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