An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 15.0 m if her initial speed is 2.40 m/s. What is the free-fall acceleration on the planet?

Answer 1

The horizontal distance covered is
X = 2 Vo^2/g sin A cos A
= (Vo^2/g) * sin (2A)
where Vo is the initial velocity and A is the takeoff angle.
Maximum range is obtained with A = 45 degrees. In this case,
X = Vo^2/g

Use this equation to solve for g

Answer 2

2.60m/s