an astronaut on a strange planet can jump a maximum horizontal distance of 15m if his initial speed is 3m/s. what is the free fall acceleration on the planet?

Answer 1

maximum range is at an angle of 45°, so solve for g in
v^2 sin2θ/g = range
9/g = 15
g = 5/3 m/s^2

Answer 2

How can i repond

Answer 3

Yes