Question

An aspirin tablet weighing 0.650 g has been analyzed and contains 68.2 % ASA (180.16 g/mol) by mass. A student dissolved
the tablet in hot NaOH and the cooled solution was diluted with DI water to the mark in a 250 mL volumetric flask. Exactly 3.00 mL
of the solution was pipetted into a 100 mL volumetric flask and diluted to the mark with FeCl3 solution.
The concentration of the diluted solution is

Answer 1

The question leaves a little to be desired. Do you want the concn in grams/mL, grams in total volume, molarity, and/or do you want the concn of the tablet?
I suspect you want the concn in g/mL in the final 100 mL volumetric flask. If that isn't so then clarify the question and repost.
0.650 x 0.682 = ?? g ASA in the tablet.

??g ASA placed in 250 mL flask. concn now ??g/250 mL = xx g/mL.
We take 3 mL and dilute to 100 so it is not xxg/mL x 3/100 = yy g/mL.
You can divide the yy by 180.16 to obtain the mols/mL and then change to to mols per 1 L to get M.Check my thinking. Check my work.