number of large --- x
number of medium -- y
number of small --- 180-x-y
6x + 5y + 4(180-x-y) = 820
6x+5y+720-4x-4y=820
2x+y=100 or y = 100-2x
22x+14y+11(180-x-y) = 2380
11x + 3y = 400
sub in y = 100-2x
11x + 3(100-2x) = 400
5x = 100
x=20
then y = 60
So 20 large, 60 medium and 100 small ones
btw, it asked for $2380 in revenue, not $2380 in profit
An artist makes three types of ceramic statues (large, medium, and small) at a monthly cost of $820 for 180 statues. The manufacturing costs for the three types are $6, $5, and $4. If the statues sell for $22, $14, and $11, respectively, how many of each type should be made to produce $2,380 in monthly revenue?
1 answer