An artist is going to sell two sizes of prints at an art fair. The artist will charge $20 for the small print and $45 for a large print. The artist would like to sell twice as many small prints as large prints. The booth the artist is renting for the day cost $510. How many of each size print must the artist sell in order to break even at the fair?

Answer 1

number of small prints --- x
number of large prints --- 2x

20x + 45(2x) = 510
20x+90x=510
110x = 510
x= 510/110 = 4.6

but you can't sell .6 of a print, so I would say he should sell 5 small and 10 large prints

check:
5(20) + 10(45) = 550 -- a profit
if he sold only 4 small and 8 large
income = 4(20) = 8(45) = 440 , not enough to cover rent.

Answer 2

You switched the large and small print numbers. Selling twice as many small prints would make it:
20 (2x) + 45 (x) = 510
If you solve with that formula in mind, x = 6...and that is the break-even number.

Answer 3

hi I THINK THE ANSWER IS 569

Answer 4

20x(2) + 45x = $510

40x + 45x =$510

85x / 85 = $510/85

x = 6

She sold twice as many small than large. So, small = 2(6) which equals 12

20(12) + 45(6) = $510

240 + 270 = $510

Answer 5

12 smalls 6 larges

Answer 6

12 small 6 large