Let \( x \) be the amount the artist invests at 6%, and let \( y \) be the amount she invests at 4%. From the problem, we know:
- \( y = 4x + 5000 \) (the amount invested at 4% is $5000 more than four times the amount invested at 6%)
- The total annual interest from both investments is $1410, represented by the equation: \[ 0.06x + 0.04y = 1410 \]
Now, we can substitute \( y \) from the first equation into the second equation.
Substituting \( y \): \[ 0.06x + 0.04(4x + 5000) = 1410 \]
Expanding the equation: \[ 0.06x + 0.16x + 200 = 1410 \]
Combine like terms: \[ 0.22x + 200 = 1410 \]
Subtracting 200 from both sides gives: \[ 0.22x = 1210 \]
Now, divide both sides by 0.22: \[ x = \frac{1210}{0.22} \approx 5500 \]
Now we can find \( y \): \[ y = 4(5500) + 5000 = 22000 + 5000 = 27000 \]
Therefore, the artist invests:
- At 6%: $5500
- At 4%: $27000
To check the total interest:
- Interest from 6% investment: \( 0.06 \times 5500 = 330 \)
- Interest from 4% investment: \( 0.04 \times 27000 = 1080 \)
- Total interest: \( 330 + 1080 = 1410 \)
Thus, the amounts are confirmed to be correct.
So, the artist invests:
- $5500 at 6%
- $27000 at 4%