An artist bought four 8-oz jars for a total of 32 oz of paint. How much would he have paid for the same amount of paint if he had instead bought the 4-oz jars?

Question

A 2-column table with 4 rows. Column 1 is labeled Paints with entries 2 ounce jar, 4 ounce jar, 8 ounce jar, 16 ounce jar. Column 2 is labeled Total price with entries 75 cents, 73 cents, 71 cents, 72 cents.

He would have paid $
if he had bought
the 4-oz jars of paint instead of the 8-oz jars.

Answer 1

To determine how much the artist would have paid for 32 oz of paint using 4-oz jars instead of 8-oz jars, we first need to understand how many 4-oz jars he would need and then calculate the total cost based on the table provided.

1. Determine the number of 4-oz jars needed: \[ \text{Total ounces needed} = 32 \text{ oz} \] \[ \text{Ounces per jar} = 4 \text{ oz} \] \[ \text{Number of jars needed} = \frac{32 \text{ oz}}{4 \text{ oz/jar}} = 8 \text{ jars} \]

2. Find the cost of one 4-oz jar: From the table:

   • The cost of a 4-oz jar is 73 cents.

3. Calculate the total cost for 8 jars: \[ \text{Cost for 8 jars} = 8 \text{ jars} \times 0.73 \text{ dollars/jar} = 5.84 \text{ dollars} \]

4. Compare to the cost of 8-oz jars: The artist spent 71 cents for one 8-oz jar, so for 4 jars: \[ \text{Cost for 4 jars} = 4 \text{ jars} \times 0.71 \text{ dollars/jar} = 2.84 \text{ dollars} \]

Now, answering the question directly: He would have paid $5.84 if he had bought the 4-oz jars of paint instead of the 8-oz jars.