An artillery shell is launched on a flat, horizontal field at an angle of α = 31.5° with respect to the horizontal and with an initial speed of v0 = 266 m/s.

Question

What is the horizontal distance covered by the shell after 9.44 s of flight?

What is the height of the shell at this moment?

Answer 1

horizontal= 266cos31.5*t
h=266sin31.5*t-4.9t^2