Vo = 1630 m/s[86o]
Yo = 1630*sin86 = 1626 m/s.
Y = Yo + g*Tr = = 0 @ max Ht.
Tr = -Yo/g = -1626/-9.8 = 166 s. = 2.77
Min.
Tf = Tr = 2.77 min. = Fall time.
Tr + Tf = 2.77 + 2.77 = 5.54 Min. = Time
in flight.
An artillery shell is fired at an angle of 86◦
above the horizontal ground with an initial
speed of 1630 m/s.
The acceleration of gravity is 9.8 m/s
2
.
Find the total time of flight of the shell,
neglecting air resistance.
Answer in units of min
1 answer
1 answer