.638 = 1(1/2)^(t/5730)
log .638 = (t/5730)log .5
t/5730 = log .638/log .5 = .64837...
t = appr 3715 years
An artifact was found with 63.8% of Carbon 14, how old is the mummy, assuming the half-life of Carbon 14 is 5730 years.
2 answers
A scientist determined that the bones from a mastodon had lost 79.579.5% of their carbon-14. How old were the bones at the time they were discovered?