Let's represent the width of the classroom as "w". According to the problem, the length of the classroom is 2.4 times the width, which means the length is 2.4w.
Now, let's set up an equation to represent this relationship: 2.4w = 42.
To find the width of the model, we need to solve for "w" in the equation. Dividing both sides of the equation by 2.4, we have: w = 42 ÷ 2.4.
Using a calculator or long division, we can find that w ≈ 17.5 (rounded to one decimal place).
Therefore, the width of the model should be approximately 17.5 inches.
An art student wants to make a model of the classroom. The length of the classroom is 2.4 times its width. The length of the student’s model is 42 in. What should the width of the model be? (1 point)
1 answer