An arrow is shot horizontally from a 50 m cliff with a velocity of 15 m/s. As the arrow travels in its parabolic path, its new height some time later, is 24 m. Calculate the instantaneous velocity of the moment it reaches is new height.

Answer 1

V^2 = Vo^2 + 2g*d.
V^2 = 0 + 19.6*(50-24) = 509.6
V = 22.6 m/s.