v = Vi + a t
152 = 0 + 1.35 * 10^4 t
but 1.35 * 10^4 = 135 * 10^2
t = (152/135) * 10^-2 = 1.13 * 10^-2
= .0113 seconds
an arrow is shot from a crossbow. How long will it take the arrow to accelerate from rest to a speed of 152 m/s if the crossbow can accelerate the arrow at a rate of 1.35 x 10^4
1 answer