Vi = 54 sin 39
v = Vi - 9.8 t
v = 0 at top
so
t = Vi/9.8 at top
use that t
h = Vi t - 4.9 t^2
it will turn out to be 1/2 Vi t
An arrow is shot at an angle 39◦ with the
horizontal. It has a velocity of 54 m/s.
How high will the arrow go? The acceleration of gravity is 9.8 m/s^2. Answer in units of m
1 answer