An arrow is shot at an angle 31 ◦ with the

Question

horizontal. It has a velocity of 47 m/s.
How high will the arrow go? The acceleration
of gravity is 9.8 m/s
2
.
Answer in units of m

Answer 1

the initial vertical speed is 47 sin 31° = 24.2 m/s

So, the height

y = 24.2t - 4.9t^2

Now use your algebra to find the vertex of that parabola. That will be the maximum height.