Vo = 52m/s[28o].
Xo = 52*Cos28 = 45.91 m/s.
Yo = 52*sin28 = 24.41 m/s.
a. Y^2 = Yo^2 + 2g*h.
0 = (24.41)^2 - 19.6h, h = ?.
b. Range = Vo^2*sin(2A)/g.
A = 28o, Range = ?.
An arrow is shot at 28.0 degrees above the horizontal. Its velocity is 52 m/s, and it hits the target.
(a) What is the maximum height the arrow will attain?
(b) The target is at the height from which the arrow was shot. How far away was it?
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