An arrow is launched vertically upward from a crossbow at 98.2 m/s. Ignoring air friction, what is its instantaneous speed at the end of 10.0 s of flight?

Question

What is its average speed up to that moment?

How high has it risen?

What is its instantaneous acceleration 4.20 s into the flight?

Answer 1

vfinal=vinitial-9.8*t

average speed= (Vi+Vf)/2

hf=Vi(10)-4.9(10^2)