An arrow is launched upward with a velocity of 54 feet per second from the top of a 75 foot building. What is the maximum height attained by the arrow in feet?

Answer 1

from your information, the height h is
h = -16t^2 + 54t +75 , where t is in seconds and h is in feet

dh/dt = -32t + 54
= 0 for a max h
32t = 54
t = 54/32 = 27/16 ---> time it took to reach max height = -16(27/16)^2 + 54(27/16) + 75
= 120.56 ft

h = -16(