An arrow is fired horizontally at a speed of 50m/s from the top of a vertical cliff overlooking the sea. The height of the cliff is 12m. Determine

The speed and angle to the horizontal of the arrow when it enters the sea?

5 answers

vertical problem
it falls from 12 m up, no initial velocity
v = -g t
h = 12 - 4.9 t^2
so at sea surface
t = sqrt (12/4.9) and v = - 9.81 t

now horizontal problem
constant u = 50
time t we just got above
so
speed = sqrt (50^2+v^2)
tan angle = v/u

Thanks Damon

How do you calculate V^2 ?

v = -g t

v = -g t
if the first equation in the vertical problem, falling object