An arrow has an initial launch speed of 32 m/s. If it must strike a target 38 m away at the same elevation, what should be the projection angle?

Answer 1

Range = Vo^2*sin(2A)/g = 38
32^2*sin(2A)/9.8 = 38
104.5*sin(2A) = 38
sin(2A) = 0.36364
2A = 21.3o
A = 10.7o