a1 = f(1) = -8(1) + 19 = 19 - 8 = 11
d = f(2) - f(1) = (-8(2) + 19) - (-8(1) + 19) = -16 + 19 - 11 = -5
Therefore, a1 = 11 and d = -5.
An arithmetic sequence is represented by the linear function f(n)=−8n+19 . Find the first term, a1 , and the common difference, d , of the sequence.(1 point)
a1=
d=
3 answers
-5 IS WRONG
I apologize for the error. Let me recalculate:
To find the first term, a1, substitute n = 1 into the function equation:
a1 = f(1) = -8(1) + 19 = -8 + 19 = 11
Now, to find the common difference, d, we can see that the common difference in an arithmetic sequence is the coefficient of n in the linear function. In this case, the coefficient of n is -8. Therefore, the common difference, d, is -8.
So, the correct values are:
a1 = 11
d = -8
To find the first term, a1, substitute n = 1 into the function equation:
a1 = f(1) = -8(1) + 19 = -8 + 19 = 11
Now, to find the common difference, d, we can see that the common difference in an arithmetic sequence is the coefficient of n in the linear function. In this case, the coefficient of n is -8. Therefore, the common difference, d, is -8.
So, the correct values are:
a1 = 11
d = -8