Let x,y be the side of each of the squares.
x2 + y2 = 1000
y=(2/3)x-10
substitute (2/3)x-10 for y in the first equation:
x2 + ((2/3)x-10)2 = 1000
Expand and solve for the quadratic equation to get x=30 or x=-270/13.
Reject second solution to get x=30, y=10
An area, A, consisting of the sum of two squares is 1000. The side of one square is 10 less than 2/3 of the side of the other square. What are the sides of the squares?
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