To find the net force on the arrow during the acceleration, we can use Newton's second law of motion, which states that the net force (F_net) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a):
F_net = m * a
Given:
Mass of the arrow (m) = 0.06 kg
Acceleration of the arrow (a) = 5,000 m/s^2
Plugging in the values into the formula, we get:
F_net = 0.06 kg * 5,000 m/s^2
= 300 N
Therefore, the net force on the arrow during the acceleration is 300 Newtons (N) to the nearest newton.
To summarize:
- Acceleration: 5,000 m/s^2
- Speed: 50.0 m/s
- Mass: 0.06 kg
- Net force: 300 N
An archer shot a 0.06 kg arrow at a target. The arrow accelerated at 5,000 m/s/s to reach a speed of 50.0 m/s as it left the bow. During this ACCELERATION, what was the net force on the arrow to the nearest newton?
and how much is the acceleration, speed, mass, or force?
1 answer