An archer shoots an arrow at a 78.0 m distant target, the bull's-eye of which is at same height as the release height of the arrow.

(a) At what angle must the arrow be released to hit the bull's-eye if its initial speed is 34.0 m/s? (Although neglected here, the atmosphere provides significant lift to real arrows.)

3 answers

Range = Vo^2*sin(2A)/g = 78 m.
34^2*sin(2A)/9.8 = 78
Solve for A.

449

20.695

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