An archer pulls her bowstring back 0.488 m by extending a force that increases uniformly from zero to 251 N.

What is the equivalent spring constant of the bow?
Answer in units of N/m.

How much work does the archer do in pulling the bow?
Answer in units of J.

1 answer

F = kx
251 = k (.488)

(1/2) k x^2 Joules