F = kx
251 = k (.488)
(1/2) k x^2 Joules
An archer pulls her bowstring back 0.488 m by extending a force that increases uniformly from zero to 251 N.
What is the equivalent spring constant of the bow?
Answer in units of N/m.
How much work does the archer do in pulling the bow?
Answer in units of J.
1 answer