Asked by Lindsey
An archer exerts an average force of 194 N to draw a 0.25 kg arrow back 1.2 m with the string of the bow.
How much work does the archer exert?
How much work does the archer exert?
Answers
Answered by
drwls
The "bow constant", which is the ratio of force F to pullback distance X, is
k = 194/1.2 = 161.7 N/m
The work done puling back the arrow is
W = (1/2) k X^2 = (1/2) F*X
The mass of the arrow is not needed to answer that question, but it will affect the arrow's velocity
k = 194/1.2 = 161.7 N/m
The work done puling back the arrow is
W = (1/2) k X^2 = (1/2) F*X
The mass of the arrow is not needed to answer that question, but it will affect the arrow's velocity
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