r=6/(4PI/9)=54/(4PI)=27/(2PI)
area of sector=PI r^2(360/80)=
= PI(6^2)(9/2)=PI18*9 check that.
An Arc of length 6 cm subtends a 80 degree angle in a circle. What is the radius of the circle? Also what is the area of that sector?
What I have so far:
S=R*80 degree
S= R*4pi/9
6 cm= r* 4pi/9
R=6/4pi/9
R= 6*9/4pi
R=54/4pi
HELP!
3 answers
Answer the following
Find the arc length and area of a sector and a circle if the arc measure is 80• and the length of the radius is 6 cm.
3 answers