An aqueous solvent of NaCl has a melting point of –165C

Question

How many moles of NaCl are present in a 189 g solvent?

Answer 1

I don't believe your numbers. -165C as the freezing point is a pretty great amount of salt.

freezingpoint=molarity*-.52

molarity=165/.52 about 300 moles/kg solvent

molesNaCl=about 300/.189 about 1600 moles salt or about more than a barrel full of salt in a beaker of water? It isn't going to happen, at least here in Texas.

Answer 2

Actually it is even worse than that since Kf is 1.86 (and not 0.52)

Answer 3

True.