An aqueous solution with a density of 0.998 g/ml at 20 degrees Celsius is prepared by dissolving 12.8 mL of CH3CH2CH2OH (p=0.803 g/mL) in enough water to make 75.0 mL of solution calculate the molarity

Answer 1

grams CH3CH2CH2OH = volume x density = 12.8 x 0.803 = ?
moles CH3CH2CH2OH = grams/molar mass
Then M = moles/L soln.
L soln = 0.075L