An aqueous solution of NaCl freezes at -1.6ºC. At what temperature will it boil? Given that K(b) for water is 0.52 deg m^-1.

Answer 1

delta T = i*Kf*m
dT = 1.6
i = 2 for NaCl
You know Kf.
Solve for m

Then dT = i*Kb*m
Solve for dT and add to 100 C to find new boiling point.